Abstract
We examine the M-theory version of SQCD which is known
as MQCD. In the IIA limit, this theory appears to have a
supersymmetry-breaking brane configuration which corresponds to
the meta-stable state of 
= 1 SU(Nc) SQCD. However, the
behavior at infinity of this non-supersymmetric brane construction
differs from that of the supersymmetric ground state of MQCD. We
interpret this to mean that it is not a meta-stable state in MQCD,
but rather a state in another theory. This provides a concrete
example of the fact that, while MQCD accurately describes the
supersymmetric features of SCQD, it fails to reproduce its
non-supersymmetric features (such as meta-stable states) not only
quantitatively but also qualitatively.
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